1035. Uncrossed Lines
LeetCode 1035. Uncrossed Lines
Description
We write the integers of A
and B
(in the order they are given) on two separate horizontal lines.
Now, we may draw connecting lines : a straight line connecting two numbers A[i]
and B[j]
such that:
A[i] == B[j]
;The line we draw does not intersect any other connecting (non-horizontal) line.
Note that a connecting lines cannot intersect even at the endpoints: each number can only belong to one connecting line.
Return the maximum number of connecting lines we can draw in this way.
Example 1:

Input: A = [1,4,2], B = [1,2,4]
Output: 2
Explanation: We can draw 2 uncrossed lines as in the diagram.
We cannot draw 3 uncrossed lines, because the line from A[1]=4 to B[2]=4 will intersect the line from A[2]=2 to B[1]=2.
Example 2:
Input: A = [2,5,1,2,5], B = [10,5,2,1,5,2]
Output: 3
Note:
1 <= A.length <= 500
1 <= B.length <= 500
1 <= A[i], B[i] <= 2000
Tags
Dynamic Programming, Array
Solution
This problem is totally the same as LeetCode 1143. Longest Common Subsequence.
Complexity
Time complexity:
Space complexity:
Code
func maxUncrossedLines(nums1 []int, nums2 []int) int {
dp := make([][]int, len(nums1)+1)
for i := range dp {
dp[i] = make([]int, len(nums2)+1)
}
for i := 1; i <= len(nums1); i++ {
for j := 1; j <= len(nums2); j++ {
if nums1[i-1] == nums2[j-1] {
dp[i][j] = 1 + dp[i-1][j-1]
} else {
dp[i][j] = max(dp[i][j-1], dp[i-1][j])
}
}
}
return dp[len(nums1)][len(nums2)]
}
func max(a, b int) int {
if a > b {
return a
}
return b
}
Reference
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