225. Implement Stack using Queues

Description

Implement a last in first out (LIFO) stack using only two queues. The implemented stack should support all the functions of a normal queue (push, top, pop, and empty).

Implement the MyStack class:

  • void push(int x) Pushes element x to the top of the stack.

  • int pop() Removes the element on the top of the stack and returns it.

  • int top() Returns the element on the top of the stack.

  • boolean empty() Returns true if the stack is empty, false otherwise.

Notes:

  • You must use only standard operations of a queue, which means only push to back, peek/pop from front, size, and is empty operations are valid.

  • Depending on your language, the queue may not be supported natively. You may simulate a queue using a list or deque (double-ended queue), as long as you use only a queue's standard operations.

Example 1:

Input
["MyStack", "push", "push", "top", "pop", "empty"]
[[], [1], [2], [], [], []]
Output
[null, null, null, 2, 2, false]

Explanation
MyStack myStack = new MyStack();
myStack.push(1);
myStack.push(2);
myStack.top(); // return 2
myStack.pop(); // return 2
myStack.empty(); // return False

Constraints:

  • 1 <= x <= 9

  • At most 100 calls will be made to push, pop, top, and empty.

  • All the calls to pop and top are valid.

Follow-up: Can you implement the stack such that each operation is amortized O(1) time complexity? In other words, performing n operations will take overall O(n) time even if one of those operations may take longer. You can use more than two queues.

Tags

Stack, Design

Solution

Here we only use a single queue to implement the stack.

  • Push: push x into the queue, then pop and push all other elements;

  • Pop: same as the queue's pop;

  • Top: return the value of the front element of the queue;

  • Empty: return the equality of the length of queue and 0.

Complexity

  • Time complexity: O(n)O(n) for Push; O(1)O(1) for others;

  • Space complexity: O(n)O(n)

Code

Reference

Last updated

Was this helpful?