225. Implement Stack using Queues
LeetCode 225. Implement Stack using Queues
Description
Implement a last in first out (LIFO) stack using only two queues. The implemented stack should support all the functions of a normal queue (push, top, pop, and empty).
Implement the MyStack class:
void push(int x)Pushes element x to the top of the stack.int pop()Removes the element on the top of the stack and returns it.int top()Returns the element on the top of the stack.boolean empty()Returnstrueif the stack is empty,falseotherwise.
Notes:
You must use only standard operations of a queue, which means only
push to back,peek/pop from front,size, andis emptyoperations are valid.Depending on your language, the queue may not be supported natively. You may simulate a queue using a list or deque (double-ended queue), as long as you use only a queue's standard operations.
Example 1:
Input
["MyStack", "push", "push", "top", "pop", "empty"]
[[], [1], [2], [], [], []]
Output
[null, null, null, 2, 2, false]
Explanation
MyStack myStack = new MyStack();
myStack.push(1);
myStack.push(2);
myStack.top(); // return 2
myStack.pop(); // return 2
myStack.empty(); // return FalseConstraints:
1 <= x <= 9At most
100calls will be made topush,pop,top, andempty.All the calls to
popandtopare valid.
Follow-up: Can you implement the stack such that each operation is amortized O(1) time complexity? In other words, performing n operations will take overall O(n) time even if one of those operations may take longer. You can use more than two queues.
Tags
Stack, Design
Solution
Here we only use a single queue to implement the stack.
Push: push
xinto the queue, then pop and push all other elements;Pop: same as the queue's pop;
Top: return the value of the front element of the queue;
Empty: return the equality of the length of queue and 0.
Complexity
Time complexity: for Push; for others;
Space complexity:
Code
Reference
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